Evaluate \(\int \sin 2x dx\)
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Correct Answer: Option C
Explanation:
\(\int \sin 2x dx = \frac{1}{2} (-\cos 2x) + k\)
\(- \frac{1}{2} \cos 2x + k\)
\(\int \sin 2x dx = \frac{1}{2} (-\cos 2x) + k\)
\(- \frac{1}{2} \cos 2x + k\)