Evaluate \(\int (2x + 3)^{\frac{1}{2}} \delta x\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
\(\int (2x + 3)^{\frac{1}{2}} \delta x\)
let u = 2x + 3, \(\frac{\delta y}{\delta x} = 2\)
\(\delta x = \frac{\delta u}{2}\)
Now \(\int (2x + 3)^{\frac{1}{2}} \delta x = \int u^{\frac{1}{2}}.{\frac{\delta x}{2}}\)
\( = \frac{1}{2} \int u^{\frac{1}{2}} \delta u\)
\( = \frac{1}{2} u^{\frac{3}{2}} \times \frac{2}{3} + k\)
\( = \frac{1}{3} u^{\frac{3}{2}} + k\)
\( = \frac{1}{3} (2x + 3)^{\frac{3}{2}} + k\)
\(\int (2x + 3)^{\frac{1}{2}} \delta x\)
let u = 2x + 3, \(\frac{\delta y}{\delta x} = 2\)
\(\delta x = \frac{\delta u}{2}\)
Now \(\int (2x + 3)^{\frac{1}{2}} \delta x = \int u^{\frac{1}{2}}.{\frac{\delta x}{2}}\)
\( = \frac{1}{2} \int u^{\frac{1}{2}} \delta u\)
\( = \frac{1}{2} u^{\frac{3}{2}} \times \frac{2}{3} + k\)
\( = \frac{1}{3} u^{\frac{3}{2}} + k\)
\( = \frac{1}{3} (2x + 3)^{\frac{3}{2}} + k\)