PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If lt; PQS = 15o find lt; QRS

PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If < PQS = 15^o find < QRS

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A 75^o
B 37\(\frac{1}{2}\)^o
C 127\(\frac{1}{2}\)^o
D 105^o

Correct Answer: Option D

Explanation:
PSO = 90^o(angle in a semicircle)
SPO = 180^o - (90^o + 15^o) = 75^o
< QRS = 108^o - 75^o
= 105^o(opposite angles in cyclic quadrilateral are supplementary)

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PQRS is a cyclic quadrilateral with PQ as diameter of the circle. If lt; PQS = 15o ...

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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