Make x the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0
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Correct Answer: Option B
Explanation:
a(b + c) + \(\frac{5}{d}\) - 2 = 0
ab + ac + \(\frac{5}{d}\) - 2 = 0
abd + \(\frac{acd}{d}\) + 5 - 2 = ab + ac + 5 - 2d
acd = 2d - 5 - abd
c = \(\frac{2d - 5 - abd}{ad}\)
a(b + c) + \(\frac{5}{d}\) - 2 = 0
ab + ac + \(\frac{5}{d}\) - 2 = 0
abd + \(\frac{acd}{d}\) + 5 - 2 = ab + ac + 5 - 2d
acd = 2d - 5 - abd
c = \(\frac{2d - 5 - abd}{ad}\)