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Solve the equation 3x2 + 6x - 2 = 0

Solve the equation 3x2 + 6x - 2 = 0
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  • A X = -1 \(\pm\) \(\frac{\sqrt{3}}{3}\)
  • B X = -1 \(\pm\) \(\frac{\sqrt{15}}{3}\)
  • C X = -2 \(\pm\) 2
  • D X = 3 \(\pm\) \(\frac{\sqrt{3}}{15}\)
Correct Answer: Option B
Explanation:
3x2 + 6x - 2 = 0
Using almighty formula i.e. x = \(\frac{b \pm \sqrt{b^2 - 4ac}}{2a}\)
a = 3, b = 6, c = -2
x = \(\frac{-6 \pm \sqrt{6^2 - 4(3)(-2)}}{2(3)}\)
x = \(\frac{-6 \pm \sqrt{36 +Â 24}}{6}\)
x = \(\frac{-6 \pm \sqrt{60}}{6}\)
x = \(\frac{-6 \pm \sqrt{4 \times 15}}{6}\)
x = \(-1 \pm \frac{\sqrt{15}}{3}\)

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