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Friday, 06 March 2026
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The minimum value of y in the equation y = x\(^2\) - 6x + 8 is

The minimum value of y in the equation y = x\(^2\) - 6x + 8 is
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  • A 8
  • B 3
  • C 7
  • D -1
Correct Answer: Option D
Explanation:
y = x\(^2\) - 6x + 8
\(\frac{dy}{dx}\) = 2x - 6
\(\frac{dy}{dx}\) = 0
2x - 6 = 0
x = 3
\(\therefore\) y = 3\(^2\) - 6(3) + 8
= 9 - 18 + 8
= -1

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