Find the eleventh term of the progression 4, 8, 16.....
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Correct Answer: Option B
Explanation:
a = 4, r = \(\frac{4}{2}\)
\(\frac{8}{4}\) = 2
n = 11
Tn = arn - 1
T11 = 4(2)11 - 1
4(2)10 = 212
since 4 = 22
= 212
a = 4, r = \(\frac{4}{2}\)
\(\frac{8}{4}\) = 2
n = 11
Tn = arn - 1
T11 = 4(2)11 - 1
4(2)10 = 212
since 4 = 22
= 212