Search SchoolNGR

Thursday, 05 March 2026
Register . Login

Factorize 4a2 - 12ab - C2 + 9b2

Factorize 4a2 - 12ab - C2 + 9b2
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
  • A 4a(a - 3b) + (3b - c)2
  • B (2a + 3b - c)(2a + 3b + c)
  • C (2a - 3b + c)(2a - 3b - c)
  • D 4a(a - 3b) + (3b + c)
Correct Answer: Option C
Explanation:
4a2 - 12ab - C2 + 9b2
rearranges: (4a2 - 12ab + 9b2) - c2
(2a - 3b)(2a - 3b) - c2 = (2a - 3b)2 - c2
= (2a - 3b + c)(2a - 3b - c)

Share question on: