What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)
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Correct Answer: Option A
Explanation:
\(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)
\(\frac{1}{2}\)(9y2 - 24xy + 16x2) = 8x2 + kxy + Ly2
\(\frac{9}{2}\)y2 - 12xy) = kxy + Ly2
k = -12 ∴ L = \(\frac{9}{2}\)
\(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)
\(\frac{1}{2}\)(9y2 - 24xy + 16x2) = 8x2 + kxy + Ly2
\(\frac{9}{2}\)y2 - 12xy) = kxy + Ly2
k = -12 ∴ L = \(\frac{9}{2}\)