In the diagram, EFGH is a cyclic quadrilateral in which EH || FG, EG and FH are chords. If < FHG = 424o and < EFH = 34o
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Correct Answer: Option C
Explanation:
< EFH = < EGH = 34o (angles n the same segment)
< GHF = < GEF = 42o(angles in the same segment)
< FOG = 42 + 34 = 76(exterior angle)
< FOG = < EOH = 76(vertically opposite angle)
< EDO = 90o, < DOE = \(\frac{76}{2}\) = 38o
< HEG = 90o - 38o = 52o
< EFH = < EGH = 34o (angles n the same segment)
< GHF = < GEF = 42o(angles in the same segment)
< FOG = 42 + 34 = 76(exterior angle)
< FOG = < EOH = 76(vertically opposite angle)
< EDO = 90o, < DOE = \(\frac{76}{2}\) = 38o
< HEG = 90o - 38o = 52o