In the figure, PQRS is a circle with ST||RQ. Find the value of x if PT = pS
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Correct Answer: Option B
Explanation:
< PST = < RQT = x(corresponding angle)
< PST = < PTS = < PTS x (PS = PT0
< SRQ = < SPT = 180o (sum of < on straight line)
< SPT = 180o - 110o = 70o
in < SPT, < PST = PTS = < PSt = 180o
2x + 70 = 180o
2x = 180o - 70o = 110o
x = \(\frac{110^o}{2}\) = 55o
< PST = < RQT = x(corresponding angle)
< PST = < PTS = < PTS x (PS = PT0
< SRQ = < SPT = 180o (sum of < on straight line)
< SPT = 180o - 110o = 70o
in < SPT, < PST = PTS = < PSt = 180o
2x + 70 = 180o
2x = 180o - 70o = 110o
x = \(\frac{110^o}{2}\) = 55o