In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠ SPR = 40°. Find ∠ PSQ
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Correct Answer: Option A
Explanation:
R = P (base ∠ s of isc Δ, ps = RS)
−R = 40°
∠ PSQ = R (∠ s in alternate segment)
−∠ PSQ = 40°
R = P (base ∠ s of isc Δ, ps = RS)
−R = 40°
∠ PSQ = R (∠ s in alternate segment)
−∠ PSQ = 40°