A triangle has vertices P(-1,6), Q(-3, -4) and R(1, -4).Find the midpoint of PQ and QR respectively.
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Correct Answer: Option D
Explanation:
Midpoint of PQ \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\
=\frac{-1+(-3)}{2};\frac{6-4}{2}\\
=\frac{-4}{2};\frac{2}{2}\\
=-2,1\)
Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\
\frac{-3+1}{2};\frac{-4-4}{2}\\
\frac{-2}{2};\frac{-8}{2}\\
-1,-4\)
Midpoint of PQ and QR = (-2,1) and (-1,-4)
Midpoint of PQ \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\
=\frac{-1+(-3)}{2};\frac{6-4}{2}\\
=\frac{-4}{2};\frac{2}{2}\\
=-2,1\)
Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\
\frac{-3+1}{2};\frac{-4-4}{2}\\
\frac{-2}{2};\frac{-8}{2}\\
-1,-4\)
Midpoint of PQ and QR = (-2,1) and (-1,-4)