Determine the value of x for which (x\(^2\) - 1) > 0
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Correct Answer: Option A
Explanation:
x\(^2\) > 0
(x+1)(x-1) > 0
x > 1 or -1 > x
x < -1 or x > 1
x\(^2\) > 0
(x+1)(x-1) > 0
x > 1 or -1 > x
x < -1 or x > 1