Find the range of values of x for which 3x - 7 \(\leq\) 0 and x + 5 > 0
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Correct Answer: Option C
Explanation:
3x - 7 \(\leq\) 0 and x + 5 > 0
3x \(\leq\) 7 and x > -5
x \(\leq\) \(\frac{7}{3}\)
∴ Range -5 < x \(\leq\) \(\frac{7}{3}\)
3x - 7 \(\leq\) 0 and x + 5 > 0
3x \(\leq\) 7 and x > -5
x \(\leq\) \(\frac{7}{3}\)
∴ Range -5 < x \(\leq\) \(\frac{7}{3}\)