A bag contains 10 balls of which 3 are red and 7 are white. Two balls are drawn at random. Find the probability of none of the balls is red, if the draw is
With replacement:
With replacement:
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Correct Answer: Option B
Explanation:
\(= P (\) lst white \() \times P (\) second white \()\)
\(=\frac{7}{10} \times \frac{7}{10}=\frac{49}{100}=0.49\)
\(= P (\) lst white \() \times P (\) second white \()\)
\(=\frac{7}{10} \times \frac{7}{10}=\frac{49}{100}=0.49\)