A bag contains 10 balls of which 3 are red and 7 are white. Two balls are drawn at random. Find the probability of none of the balls is red, if the draw is
Without replacement
Without replacement
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Correct Answer: Option B
Explanation:
\(\frac{7}{10} \times \frac{6}{9}=0.47\)
\(\frac{7}{10} \times \frac{6}{9}=0.47\)