Question 356:
Given that \(f : x \to \frac{2x - 1}{x + 2}, x \neq -2\), find \(f^{-1}\), the inverse of f.
- A \(f^{-1} : x \to \frac{1+2x}{2-x}, x \neq 2\)
- B \(f^{-1} : x \to \frac{1-2x}{x+2}, x \neq -2\)
- C \(f^{-1} : x \to \frac{1-2x}{x-2}, x \neq 2\)
- D \(f^{-1} : x \to \frac{1+2x}{x+2}, x \neq -2\)
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