A metal cube of volume 103mm3 is lowered into a measuring cylinder containing water. If the internal cross-sectional area of the cylinder is 1.5 x 102mm2, by how much does the water level rise in the cylinder?
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Correct Answer: Option A
Explanation:
Height = \(\frac{volume}{area}\)
= Height = \(\frac{10^3}{1.5 \times 10^2}\)
= 6.67mm
Height = \(\frac{volume}{area}\)
= Height = \(\frac{10^3}{1.5 \times 10^2}\)
= 6.67mm