A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?
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Correct Answer: Option E
Explanation:
Height inside H2O = \(\frac{2}{3}\)
R.d = \(\frac{\text{height inside}H_2O}{\text{height inside liquid}}\)
0.8 = \(\frac{\frac{2}{3}}{X}\)
Height inside H2O = \(\frac{2}{3}\)
R.d = \(\frac{\text{height inside}H_2O}{\text{height inside liquid}}\)
0.8 = \(\frac{\frac{2}{3}}{X}\)