A thin aluminum plate has a surface area of 1500m[/sup] at 20[sup]oC. What will be its surface area when it is cooled to -20oC? (Take the linear expansivity of aluminum to be 2.5 x 10-5k-1).
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Correct Answer: Option C
Explanation:
\(\beta\) = A2 - A1
2 X 10-5 x 2.5 = \(\frac{A_2 \times 1.5}{1.5 \times (-20 -20)}\)
A2 = 1.498m2
\(\beta\) = A2 - A1
2 X 10-5 x 2.5 = \(\frac{A_2 \times 1.5}{1.5 \times (-20 -20)}\)
A2 = 1.498m2