A pool of water appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.33, what is the actual depth of the pool?
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Correct Answer: Option C
Explanation:
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm
n = \(\frac{\text {real depth}}{\text{apparent depth}}\)
1.33 = \(\frac{\text {real depth}}{1}\)
real depth = 1.33cm