A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms[/sup]. If the acceleration due to gravity is 10ms[sup]-1, the coefficient of friction between the moving mass and the table is
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Correct Answer: Option A
Explanation:
\(\mu\)mg = ma
\(\mu\) x 10 x 10 = 10 x 0.2
\(\mu\) = 0.02
\(\mu\)mg = ma
\(\mu\) x 10 x 10 = 10 x 0.2
\(\mu\) = 0.02