A body whose mass is 2kg and has a volume of 500cm3 just floats when completely immersed in a liquid. Calculate the density of the liquid
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Correct Answer: Option B
Explanation:
since the object floats, density of liquid = density of object
converting 500cm3 to m3,
\(\frac{500}{10^{6}} = 5 \times 10^{-4}m^{3}\)
D = \(\frac{m}{v}\)
= \(\frac{2}{5 \times 10^{-4}}\)
=\(4.0 \times 10^{3}kgm^{-3}\)
since the object floats, density of liquid = density of object
converting 500cm3 to m3,
\(\frac{500}{10^{6}} = 5 \times 10^{-4}m^{3}\)
D = \(\frac{m}{v}\)
= \(\frac{2}{5 \times 10^{-4}}\)
=\(4.0 \times 10^{3}kgm^{-3}\)