Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding ratio of
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Correct Answer: Option D
Explanation:
F = \(\frac{1}{2L}\)\(\sqrt\frac{T}{m}\)
\(\frac{F_1}{F_2}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\frac{1}{4}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\sqrt\frac{m_2}{m_1}\) = \(\frac{1}{16}\)
F = \(\frac{1}{2L}\)\(\sqrt\frac{T}{m}\)
\(\frac{F_1}{F_2}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\frac{1}{4}\) = \(\sqrt\frac{m_2}{m_1}\)
\(\sqrt\frac{m_2}{m_1}\) = \(\frac{1}{16}\)