To obtain a magnification of 2.5, how far should an object be placed from the pole of a thin converging lens of focal length 10.20m?
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Correct Answer: Option C
Explanation:
v = 2.5u
F = \(\frac {uv}{u + v}\)
0.2 = \(\frac {u \times 2.5u}{u + 2.5u}\)
u = 0.28m
v = 2.5u
F = \(\frac {uv}{u + v}\)
0.2 = \(\frac {u \times 2.5u}{u + 2.5u}\)
u = 0.28m