An object is placed 10cm in front of a concave mirror of focal length 15cm. What is the position and nature of the image formed?
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Correct Answer: Option A
Explanation:
F = \(\frac{uv}{u + v}\)
15 = \(\frac{10 \times v}{10 + v}\)
v = -30cm
F = \(\frac{uv}{u + v}\)
15 = \(\frac{10 \times v}{10 + v}\)
v = -30cm