A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. The efficiency of the cell is
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Correct Answer: Option D
Explanation:
Efficiency = \(\frac{IR}{I(R + r)}\) x 100
= \(\frac{6}{I(2 + 6)}\) x 100
= 75%
Efficiency = \(\frac{IR}{I(R + r)}\) x 100
= \(\frac{6}{I(2 + 6)}\) x 100
= 75%