When a resistance R is across a cell, the voltage across the terminals of the cell is reduced to two-third of its normal value. The internal resistance of the cell is
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Correct Answer: Option B
Explanation:
IR = \(\frac{2}{3}\) I(R + r)
r = \(\frac{1}{2}\)R
IR = \(\frac{2}{3}\) I(R + r)
r = \(\frac{1}{2}\)R