When the volume of a given mass of gas is halved and its temperature doubled, the pressure
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Correct Answer: Option B
Explanation:
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2 and T2 = 2T1
\(\frac{P_1\times 2V_2}{T_1}\) = \(\frac{P_2\times V_2}{2T_1}\)
P2 = 4P1
\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)
V1 = 2V2 and T2 = 2T1
\(\frac{P_1\times 2V_2}{T_1}\) = \(\frac{P_2\times V_2}{2T_1}\)
P2 = 4P1