200g of water at 90°C is mixed with 100g of water at 30°C. What is the final temperature?
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Correct Answer: Option C
Explanation:
Heat lost = heat gained
200 x c x (90 - \(\theta\))= 100\(\times\) c \(\times\) (\(\theta - 30\))
Dividing through by 100c, we have
2(\(90 - \theta\)) = (\(\theta - 30\))
simplifying, we have
\(\theta\) = 70°
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Heat lost = heat gained
200 x c x (90 - \(\theta\))= 100\(\times\) c \(\times\) (\(\theta - 30\))
Dividing through by 100c, we have
2(\(90 - \theta\)) = (\(\theta - 30\))
simplifying, we have
\(\theta\) = 70°
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