A parallel plate capacitor of area 10cm2 in vacuum has a capacitance of 10-2\(\mu\)F. What is the distance between the plates?(e[sub][/sub] = 9 x 10-12fm)
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Correct Answer: Option B
Explanation:
C = \(\frac {\varepsilon_o\ A}{d}\)
10-2 x 10-6 = \(\frac {9 \times 10 ^{-12}}{d}\) x 10-4
= 9 x 10-7m
C = \(\frac {\varepsilon_o\ A}{d}\)
10-2 x 10-6 = \(\frac {9 \times 10 ^{-12}}{d}\) x 10-4
= 9 x 10-7m