A 40-W instrument has a resistance of 90\(\Omega\). On what voltage should it be operated normally?
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Correct Answer: Option A
Explanation:
P = \(\frac{V}{R}\)
V = \(\sqrt{PR}\)
V = \(\sqrt{40 \times 90}\)
= 60V
P = \(\frac{V}{R}\)
V = \(\sqrt{PR}\)
V = \(\sqrt{40 \times 90}\)
= 60V