What effort will a machine of efficiency 90% apply to lift a load of 180N if its efforts arm is twice as long as its load arm?
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Correct Answer: Option C
Explanation:
M.A. = \(\frac{Eff \times V.R.}{100}\)
M.A. = \(\frac{90 \times 2}{100}\)
M.A. = 1.8
E = \(\frac{L}{M.A.}\)
E = \(\frac{180}{1.8}\)
E = 100N
M.A. = \(\frac{Eff \times V.R.}{100}\)
M.A. = \(\frac{90 \times 2}{100}\)
M.A. = 1.8
E = \(\frac{L}{M.A.}\)
E = \(\frac{180}{1.8}\)
E = 100N