Calculate the work done when a force of 20N stretches a spring by 50mm.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
W = \(\frac{1}{2}Fe\)
W = \(\frac{1}{2}\times 20 \times 0.05\)
W = 0.5J
W = \(\frac{1}{2}Fe\)
W = \(\frac{1}{2}\times 20 \times 0.05\)
W = 0.5J