A charge of 1.0 x 10-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?
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Correct Answer: Option B
Explanation:
F = qE; E = F/q = 40/(1.0 x 10-5) = 4.0 x 106
F = qE; E = F/q = 40/(1.0 x 10-5) = 4.0 x 106