If the frequency of the ac. circuit illustrated above is 500/π Hz what would be the reactance in the circuit?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
= 2ufl - 1/2ufc = (2 x (500/π) x 0.9) -
1/2 x (500/π) x 2 x 0-6
= 1440Ω
= 2ufl - 1/2ufc = (2 x (500/π) x 0.9) -
1/2 x (500/π) x 2 x 0-6
= 1440Ω