a beam PQ pivoted at P carries a load of 80N as shown above. Calculate the effort E, required to keep it horizontal. [neglect the weight of the beam]
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Correct Answer: Option D
Explanation:
E x 3 = 80 x 0.5
E3 = 40
E = \(\frac{40}{3} = 13.3N\)
E x 3 = 80 x 0.5
E3 = 40
E = \(\frac{40}{3} = 13.3N\)