A resistance thermometer has a resistance of 20\(\Omega\) at 0oC and 85\(\Omega\) at 100oC. If its resistance is 52\(\Omega\)in a medium, calculate the corresponding temperature
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Correct Answer: Option A
Explanation:
85\(\Omega\) ........100oC
52\(\Omega\) ........\(\theta\)oC
20\(\Omega\) ........0oC
\(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\)
\(\theta = \frac{32 \times 100}{65} = 49.2^oC\)
85\(\Omega\) ........100oC
52\(\Omega\) ........\(\theta\)oC
20\(\Omega\) ........0oC
\(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\)
\(\theta = \frac{32 \times 100}{65} = 49.2^oC\)