The refractive index of a medium relative to air is 1.8. Calculate to the nearest degree, the critical angle for the medium
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Correct Answer: Option C
Explanation:
c = \(\sin^{-1} \frac{1}{n} = \sin^{-1} \frac{1}{1.8} = 34^o\)
c = \(\sin^{-1} \frac{1}{n} = \sin^{-1} \frac{1}{1.8} = 34^o\)