A converging lens of focal length 15cm forms a virtual image at a point 10cm from the lens. Calculate the distance of the object from the lens
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Correct Answer: Option B
Explanation:
\(\frac{1}{u} + \frac{1}{v} = \frac{1}{f} = \frac{1}{15} + \frac{1}{10}\)
u = 6.00
\(\frac{1}{u} + \frac{1}{v} = \frac{1}{f} = \frac{1}{15} + \frac{1}{10}\)
u = 6.00