Two similar cells are used to light two similar lamps as illustrated in the diagrams above. In which of the circuit diagrams are the lamps brightest?
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Correct Answer: Option A
Explanation:
The determinant of the brightness of a bulb is the power (watts) of the circuit.
Recall that Power (P) = \(\frac{V^2}{R}\).
Since the resistance is to be used as a divisor, it means the smaller the resistance, the greater the power.
The determinant of the brightness of a bulb is the power (watts) of the circuit.
Recall that Power (P) = \(\frac{V^2}{R}\).
Since the resistance is to be used as a divisor, it means the smaller the resistance, the greater the power.