A 120\(\Omega\) resistor dissipates 8 kJ of heat in 20s. Calculate the current through the resistor
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Correct Answer: Option A
Explanation:
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8
Q = I2Rt
I = \(\sqrt{\frac{Q}{Rt}}\)
= \(\sqrt{\frac{8000}{12 \times 20}}\)
= 5.8