The bob of a simple pendulum takes 8.0s to complete 10 oscillations. Determine the frequency of oscillation of the bob.
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Correct Answer: Option B
Explanation:
10 complete oscillations = 8.0s
1 complete oscillation (period) = \(\frac{8}{10}\)s
Frequency = \(\frac{1}{period}\) = \(\frac{1}{0.8} = 1.25Hz\)
10 complete oscillations = 8.0s
1 complete oscillation (period) = \(\frac{8}{10}\)s
Frequency = \(\frac{1}{period}\) = \(\frac{1}{0.8} = 1.25Hz\)