Waec Further Mathematics Questions
Question 731:
Simplify; \(\frac{\sqrt{5} + 3}{4 - \sqrt{10}}\)
- A \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + 2
- B \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\)
- C \(\frac{2}{3}\)\(\sqrt{5}\) + \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\) + 2
- D \(\frac{2}{3}\)\(\sqrt{5}\) - \(\frac{5}{6}\sqrt{2}\) + \(\frac{1}{2}\sqrt{10}\) + 2
Question 732:
If \(\frac{6x + k}{2x^2 + 7x - 15}\) = \(\frac{4}{x + 5} - \frac{2}{2x - 3}\). Find the value of k.
View Answer & ExplanationQuestion 733:
Differentiate \(\frac{x}{x + 1}\) with respect to x.
- A \(\frac{x}{x + 1}\)
- B \(\frac{-1}{x + 1}\)
- C \(\frac{1 - x}{(x + 1)^2}\)
- D \(\frac{1}{(x + 1)^2}\)
Question 735:
Given that X : R \(\to\) R is defined by x = \(\frac{y + 1}{5 - y}\) , y \(\in\) R, find the domain of x.
- A {y : y \(\in\) R, y \(\neq\) 0}
- B {y : y \(\in\) R, y \(\neq\) 1}
- C {y : y \(\in\) R, y \(\neq\) 5}
- D {y : y \(\in\) R, y \(\neq\) 7}