Jamb 1985 Mathematics Questions
Question 41:
In \(\bigtriangleup\) XYZ, XKZ = 90O, XK = 15cm, XY = 35cm and YK = 8cm. Find the area of \(\bigtriangleup\)XYZ
- A 190 sq.cm
- B 20 sq.cm
- C 210 sq.cm
- D 160sq.cm
- E 320sq.cm
Question 42:
In the figure, MNQP is a cyclic quadrilateral. MN and Pq are produced to meet at X and NQ and MP are produced to meet at Y. If MNQ = 86o and NQP = 122o find (xo, yo)
- A 28<sup style='font-size: smaller;'>o</sup>, 36<sup style='font-size: smaller;'>o</sup>
- B 36<sup style='font-size: smaller;'>o</sup>, 28<sup style='font-size: smaller;'>o</sup>
- C 43<sup style='font-size: smaller;'>o</sup>, 61<sup style='font-size: smaller;'>o</sup>
- D 61<sup style='font-size: smaller;'>o</sup>, 43<sup style='font-size: smaller;'>o</sup>
- E 36<sup style='font-size: smaller;'>o</sup>, 43<sup style='font-size: smaller;'>o</sup>
Question 43:
In the figure POQ is the diameter of the circle PQR. If PSR = 145o, find xo
- A 25<sup style='font-size: smaller;'>o</sup>
- B 35<sup style='font-size: smaller;'>o</sup>
- C 45<sup style='font-size: smaller;'>o</sup>
- D 125<sup style='font-size: smaller;'>o</sup>
- E 55<sup style='font-size: smaller;'>o</sup>
Question 44:
In the figure, GHIJKLMN is a cube of side a. Find the length of HN.
- A \(\sqrt{3a}\)
- B 3a
- C 3a<sup style='font-size: smaller;'>2</sup>
- D A\(\sqrt{2}\)
- E A\(\sqrt{3}\)
Question 45:
In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = \(\theta\)oand RQP = \(\phi\)o, which of the following relationships between \(\theta\)o and \(\phi\)o is correct
- A \(\theta\)<sup style='font-size: smaller;'>o</sup> + \(\phi\)<sup style='font-size: smaller;'>o</sup> = 90<sup style='font-size: smaller;'>2</sup>
- B \(\phi\)<sup style='font-size: smaller;'>o</sup> = 90<sup style='font-size: smaller;'>2</sup> - 2\(\theta\)<sup style='font-size: smaller;'>o</sup>
- C \(\theta\)<sup style='font-size: smaller;'>o</sup> = \(\phi\)<sup style='font-size: smaller;'>o</sup>
- D \(\phi\)<sup style='font-size: smaller;'>o</sup> = 2\(\theta\)<sup style='font-size: smaller;'>o</sup>
- E \(\theta\)<sup style='font-size: smaller;'>o</sup> + 2\(\phi\)<sup style='font-size: smaller;'>o</sup>