A charge of 2.0 x 10\(^{-5}\) C experiences a force of 80N in a uniform electric field. Calculate the magnitude of the electric field intensity
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Correct Answer: Option B
Explanation:
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)