A potential difference of 12V is applied across the ends of a 6\(\Omega\) resistor for 10 minutes. Determine the quantity of heat generated
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
Q = \(\frac{V^2 t}{R}
= \frac{12^2 \times 10 \times 60}{6}\)
= 14400J
Q = \(\frac{V^2 t}{R}
= \frac{12^2 \times 10 \times 60}{6}\)
= 14400J